Homework should be turned in, in class, on the due date. No late homework accepted, except with prior agreement of the instructor.
Each problem is worth 10 points, unless otherwise noted.
The setup for the next several problems: U is an open set in Rn, K is a compact subset of U, C is a compact, Jordan-measureable (definition: Spivak, p. 56) subset of Kint, g is a C1 diffeomorphism from U to Rn.
If you follow this hint, carefully write out the proof of every statement in the preceding paragraph!]
&intg(C)f = &intC f &omicron g |det g'|
[Hint: you will need to keep around the partition of unity from the last problem, and observe that {&phi_i &omicron g} is a partition of unity for C, with similar properties.]
v(A(K)) = det(A) v(K)
[Notes: volume of a Jordan-measureable set is defined on p. 56 in Spivak. In the preceding equation, I have confounded the name of A with the name of its matrix in the standard basis. Note that Spivak proposes an "elementary" proof of this fact in problem 3-35, and uses it in his proof of the C-of-V theorem (3-13). I used one of the three special cases listed in 3-35 in my proof of the C-of-V theorem. The second case is actually a bit involved; Lang works through it in detail. On the other hand the third case, which I used, is trivial. So you get the whole thing from the (trivial) third case and the rest of the proof of the C-of-V formula, which you had to go through anyway.]
&omega1x=x1e1* + x2e2* + x3e3*
and the alternating 2-tensor
&omega2x= x1e2* &and e3* + x2e3* &and e1* + x3e1* &and e2*.
Show that for any x,y &isin R3,
&omega1x &and &omega1y = &omega2x × y.
The following problems develop standard integration rules for the disk and circle in R2. Similar rules hold for the ball and sphere in R3, involving spherical coordinates.
[Hint: you need to exhibit an explicit atlas of charts. In view of the next problem, I suggest a family of atlases depending on a parameter &epsilon > 0, as follows: define open sets
U1={x=(x1,x2): &epsilon < |x| < 1+&epsilon, -1+&epsilon < x1/|x|},
U2={x=(x1,x2): -1 + &epsilon < x1 < 2 &epsilon, -2 &epsilon < x2 < 2 &epsilon},
and
U3={x=(x1,x2): -1 - 2&epsilon < x1 < -1+2 &epsilon, -2 &epsilon < x2 < 2 &epsilon}.
So U1 is an annulus with a thin pie-slice cut out of it around the negative x1 axis, U2 is a long thin rectangle with area approximately &epsilon, and U3 is a square of area 4 &epsilon2. These overlap and cover D. Now choose for your chart maps
(1) (essentially) polar coordinates in U1: c1(x)=(r(x)-1, &theta(x)), r(x)=|x|, &theta(x)=the unique solution of cos &theta = x1/|x|, sin &theta = x2/|x| between -&pi and +&pi (see Spivak problem 3-41 (b) for an explicit description);
(2) c2(x)=(x1-1,x2) (this is just shifting every point to the left by 1 in the first ("x") direction - note that U2 is a subset of Dint, and shifting it to the left by 1 puts its image in the interior of the half-space {x1<1}.);
(3) c3(x)=(r(x)-1,-x2).
Check that
(1) each of the c's is a diffeomorphism,
(2) ci maps Ui &cap D to H = {x: x1 &le 0}, i=1,2,3;
(3) for each i, C &cap Ui = {x &isin D &cap Ui: ci,1(x)=0}, that is, ci maps C &cap Ui into &part H &cap ci(Ui);
(4) The restrictions of the charts ci to C make C into an oriented submanifold of R2: oriented means that the overlap maps ci o cj-1 are orientation preserving, i.e. have Jacobian determinant > 0, and this is the only thing you have to check.
Taking care of (4) is a lot easier if you remember that U2 doesn't intersect C so you can forget about c2 and need only check one overlap map, and c1-1(r,&theta)=(r cos &theta, r sin &theta). Also note that in the overlap U1 &cap U3, &theta is near ± &pi . End of Hint]
∫D f dx1 &and dx2 = ∫01 ∫-&pi&pi r dr d&theta f(r cos &theta, r sin &theta).
[Hint: Use the atlas family constructed in the previous paragraph. Split the integral on the LHS into a sum of three using a partition of unity subordinate to the atlas. Bound the integrals coming from U2 and U3 by multiples of &epsilon and &epsilon2 respectively, and show that the integral over U1 converges to the RHS as &epsilon &rarr 0. Thus the LHS converges to the RHS as &epsilon &rarr 0. Since both LHS and RHS are actually independent of &epsilon, they must have been equal in the first place.]
∫C &omega1F = ∫-&pi&pi d&theta (F2(cos &theta, sin &theta) cos &theta -F1(cos &theta, sin &theta) sin &theta)
[Note: you will need to construct an argument similar to the one used in the previous problem.]
∫C x dy - y dx = 2 π.
∫-&pi&pi d&theta (F1(cos &theta, sin &theta) cos &theta +F2(cos &theta, sin &theta) sin &theta) = ∫D &part F1/&part x1 + &part F2/&part x2.
&part F1/&part x1 + &part F2/&part x2 = 0
at every point (diction: F is "divergence-free"). Denote by n the outward unit normal on either circle, regarded as the boundary of the disk of the same radius. Show that
∫C1 FT n = ∫C2 FT n.
[Hint: Let A be the annulus bounded by the two circles. The boundary of A is the union of the two circles; on the outer circle, the outward unit normal of A is the same as the outward unit normal of the the disk of the larger radius; on the inner circle, the outward unit normal of A is the negative of the outward unit normal of the disk of the smaller radius. Apply the Divergence Theorem.]